Cofactor (mathematics)

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In mathematics, a cofactor appears in the definition of the determinant of a square matrix.

Let M be a square matrix of size n. The (i,j) minor refers to the determinant of the (n-1)×(n-1) submatrix Mi,j formed by deleting the i-th row and j-th column from M (or sometimes just to the submatrix Mi,j itself). The corresponding cofactor is the signed minor

(-1)^{i+j} \det M_{i,j} . \,

The adjugate matrix adj M (in older literature called adjoint matrix[1]) is the n×n matrix whose (i,j) entry is the (j,i) cofactor (note the transposition of the indices). Letting In be the n×n identity (unit) matrix, we have

M \cdot \mathop{\mbox{adj}} M = \mathop{\mbox{adj}} M \cdot M = (\det M)\; I_n   ,\,

which encodes the rule for expansion of the determinant of M by any the cofactors of any row or column. This expression shows that if det(M) is non-zero, then M is invertible and its inverse is the following,

M^{-1} = (\det M)^{-1} \mathop{\mbox{adj}} M . \,

A proof of this equation may be found in this article.

[edit] Example

Consider the following example matrix,


M = \begin{pmatrix}
a_1 & a_2 & a_3 \\
b_1 & b_2 & b_3 \\
c_1 & c_2 & c_3 \\
\end{pmatrix}.

Its minors are the determinants (vertical bars indicate a determinant):


M_{11} = 
\begin{vmatrix}
 b_2 & b_3 \\
 c_2 & c_3 \\
\end{vmatrix}\quad
M_{12} =
\begin{vmatrix}
b_1  & b_3 \\
c_1  & c_3 \\
\end{vmatrix} \quad
M_{13} =
\begin{vmatrix}
b_1  & b_2 \\
c_1  & c_2 \\
\end{vmatrix} \quad
M_{21} =
\begin{vmatrix}
a_2  & a_3 \\
c_2  & c_3 \\
\end{vmatrix} \quad
M_{22} =
\begin{vmatrix}
a_1  & a_3 \\
c_1  & c_3 \\
\end{vmatrix} \quad

M_{23} = 
\begin{vmatrix}
 a_1 & a_2 \\
 c_1 & c_2 \\
\end{vmatrix}\quad
M_{31} =
\begin{vmatrix}
a_2  & a_3 \\
b_2  & b_3 \\
\end{vmatrix} \quad
M_{32} =
\begin{vmatrix}
a_1  & a_3 \\
b_1  & b_3 \\
\end{vmatrix} \quad
M_{33} =
\begin{vmatrix}
a_1  & a_2 \\
b_1  & b_2 \\
\end{vmatrix} \quad

The adjugate matrix of M is


\mathrm{adj}M = A =
\begin{pmatrix}
 M_{11} & -M_{21} &  M_{31} \\
-M_{12} &  M_{22} & -M_{32} \\
 M_{13} & -M_{23} &  M_{33} \\
\end{pmatrix},

and the inverse matrix is


M^{-1} = |M|^{-1} A\, .

Indeed,


\begin{align}
\left( M\; M^{-1}\right)_{11} & = |M|^{-1}\left( a_1 M_{11}- a_2 M_{12} + a_3 M_{13}\right) = \frac{|M|}{|M|} = 1 \\
\left( M\; M^{-1}\right)_{21} & = |M|^{-1}\left( b_1 M_{11}- b_2 M_{12} + b_3 M_{13}\right)
 =|M|^{-1}\left[ b_1(b_2c_3-b_3c_2) - b_2(b_1c_3-b_3c_1) + b_3(b_1c_2-b_2c_1)\right] = 0 ,\\
\end{align}

and the other matrix elements of the product follow likewise.

[edit] Note

  1. The term "adjoint" for the adjugate matrix is disappearing because it is felt that it is easily confused with Hermitian adjoint, the transpose and complex conjugate of a matrix.

[edit] References

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